Box 2 example hw set 3 problem 2 15 volts r110 ohms

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Box 2
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Example: HW Set 3 Problem #2 + - 1.5 Volts R1=10 Ohms; R2=20 Ohms; R3=30 Ohms R4= 40 Ohms Use the Mesh Current method to solve for all of the mesh currents in the above circuit , and to solve for vab R2 R3 R1 Node a Node b R4 i2 i1 i3 (i1 - i2) x 10 Ohms - 1.5V = 0V i2 x 20 Ohms + (i2-i3) x 30 Ohms + (i2-i1) x 10 Ohms = 0V i3 x 40 Ohms + (i3-i2) x 30 Ohms = 0V i1 = 190.4ma i2= 40.4mA i3= 17.3mA Vab = 692mV
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Example + - 1.5 Volts R1=10 Ohms; R2=20 Ohms; R3=30 Ohms R4= 40 Ohms Solve for i4 and vab R2 R3 R1 Node a Node b R4 i4
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Example + - 1.5 Volts R2 R3 R1 Node a Node b R1=10 Ohms; R2=20 Ohms; R3=30 Ohms Solve for the open circuit voltage, VThevenin , and the short circuit current. Then solve for RThevenin VThevenin = 1.5 Volts x 30 Ohms / (20 Ohms + 30 Ohms) = 0.9 Volts The short circuit current = 1.5Volts / 20 Ohms = 0.075 Amperes RThevenin = 0.9 Volts / 0.075 Amperes = 12 Ohms
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Example + - 0.9V R4= 40 Ohms Solve for i4 and vab i4 = 0.9V / ( 12 + 40 29 = 0.017308A Vab = 0.017308A x 40 = 0.69231V 12 Node a Node b R4 i4
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Replacing a box containing sources and resistors with its Norton Equivalent Circuit
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What is inside the box? + - c b V= 60V 10 20 What is the “open circuit” voltage? Answer: 60V x 20 Ω / 30 = 40V What is the “short circuit” current? Answer: 60V / 10 = 6A What is the ratio of open circuit voltage to short circuit current? Answer: 40V / 6A = 6.667 (rounded to 4 significant figures) Box 1
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What is inside the box? c b i= 6A 6.667 From the outside of the box , given access only to terminals c and d, one cannot observe any difference between this box (Box 3) and the previous box (Box 1) The circuit inside this box is called the Norton Equivalent circuit for the circuitry inside Box 1. Box 3
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Example: HW Set 3 Problem #2 + - 1.5 Volts R1=10 Ohms; R2=20 Ohms; R3=30 Ohms R4= 40 Ohms Use the Mesh Current method to solve for all of the mesh currents in the above circuit , and to solve for vab R2 R3 R1 Node a Node b R4 i2 i1 i3 (i1 - i2) x 10 Ohms - 1.5V = 0V i2 x 20 Ohms + (i2-i3) x 30 Ohms + (i2-i1) x 10 Ohms = 0V i3 x 40 Ohms + (i3-i2) x 30 Ohms = 0V i1 = 190.4ma i2= 40.4mA i3= 17.3mA Vab = 692mV
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Example + - 1.5 Volts R1=10 Ohms; R2=20 Ohms; R3=30 Ohms R4= 40 Ohms Solve for i4 and vab R2 R3 R1 Node a Node b R4 i4
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Example + - 1.5 Volts R2 R3 R1 Node a Node b R1=10 Ohms; R2=20 Ohms; R3=30 Ohms Solve for the open circuit voltage, VThevenin , and the short circuit current. Then solve for RThevenin VThevenin = 1.5 Volts x 30 Ohms / (20 Ohms + 30 Ohms) =
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  • Fall '08
  • PIETRUCHA
  • Volt, Ohms, Thévenin's theorem, rth, Vab

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