# Box 2 example hw set 3 problem 2 15 volts r110 ohms

• Notes
• 33

This preview shows page 10 - 21 out of 33 pages.

Box 2

Subscribe to view the full document.

Example: HW Set 3 Problem #2 + - 1.5 Volts R1=10 Ohms; R2=20 Ohms; R3=30 Ohms R4= 40 Ohms Use the Mesh Current method to solve for all of the mesh currents in the above circuit , and to solve for vab R2 R3 R1 Node a Node b R4 i2 i1 i3 (i1 - i2) x 10 Ohms - 1.5V = 0V i2 x 20 Ohms + (i2-i3) x 30 Ohms + (i2-i1) x 10 Ohms = 0V i3 x 40 Ohms + (i3-i2) x 30 Ohms = 0V i1 = 190.4ma i2= 40.4mA i3= 17.3mA Vab = 692mV
Example + - 1.5 Volts R1=10 Ohms; R2=20 Ohms; R3=30 Ohms R4= 40 Ohms Solve for i4 and vab R2 R3 R1 Node a Node b R4 i4

Subscribe to view the full document.

Example + - 1.5 Volts R2 R3 R1 Node a Node b R1=10 Ohms; R2=20 Ohms; R3=30 Ohms Solve for the open circuit voltage, VThevenin , and the short circuit current. Then solve for RThevenin VThevenin = 1.5 Volts x 30 Ohms / (20 Ohms + 30 Ohms) = 0.9 Volts The short circuit current = 1.5Volts / 20 Ohms = 0.075 Amperes RThevenin = 0.9 Volts / 0.075 Amperes = 12 Ohms
Example + - 0.9V R4= 40 Ohms Solve for i4 and vab i4 = 0.9V / ( 12 + 40 29 = 0.017308A Vab = 0.017308A x 40 = 0.69231V 12 Node a Node b R4 i4

Subscribe to view the full document.

Replacing a box containing sources and resistors with its Norton Equivalent Circuit
What is inside the box? + - c b V= 60V 10 20 What is the “open circuit” voltage? Answer: 60V x 20 Ω / 30 = 40V What is the “short circuit” current? Answer: 60V / 10 = 6A What is the ratio of open circuit voltage to short circuit current? Answer: 40V / 6A = 6.667 (rounded to 4 significant figures) Box 1

Subscribe to view the full document.

What is inside the box? c b i= 6A 6.667 From the outside of the box , given access only to terminals c and d, one cannot observe any difference between this box (Box 3) and the previous box (Box 1) The circuit inside this box is called the Norton Equivalent circuit for the circuitry inside Box 1. Box 3
Example: HW Set 3 Problem #2 + - 1.5 Volts R1=10 Ohms; R2=20 Ohms; R3=30 Ohms R4= 40 Ohms Use the Mesh Current method to solve for all of the mesh currents in the above circuit , and to solve for vab R2 R3 R1 Node a Node b R4 i2 i1 i3 (i1 - i2) x 10 Ohms - 1.5V = 0V i2 x 20 Ohms + (i2-i3) x 30 Ohms + (i2-i1) x 10 Ohms = 0V i3 x 40 Ohms + (i3-i2) x 30 Ohms = 0V i1 = 190.4ma i2= 40.4mA i3= 17.3mA Vab = 692mV

Subscribe to view the full document.

Example + - 1.5 Volts R1=10 Ohms; R2=20 Ohms; R3=30 Ohms R4= 40 Ohms Solve for i4 and vab R2 R3 R1 Node a Node b R4 i4
Example + - 1.5 Volts R2 R3 R1 Node a Node b R1=10 Ohms; R2=20 Ohms; R3=30 Ohms Solve for the open circuit voltage, VThevenin , and the short circuit current. Then solve for RThevenin VThevenin = 1.5 Volts x 30 Ohms / (20 Ohms + 30 Ohms) =

Subscribe to view the full document.

You've reached the end of this preview.
• Fall '08
• PIETRUCHA
• Volt, Ohms, Thévenin's theorem, rth, Vab

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern