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36920.3108.365 10KAt a load of 18 kN, life L1is given by: 961318.365 101.43410rev18aKLFFor a load of 30 kN, life L2is: 96238.365 100.31010rev30LTherefore; 12121llLLSubstituting, 266200 00011.434 100.310 10lProblem 3 Solution Total life in revolutionsl= total turns f1= fraction of turns at F1f2= fraction of turns at F2From the solution of previous problem L1= 1.434(106) rev and L2= 0.310(106) rev. Therefore: 121212121llf lf lLLLLfrom which 11221//lfLfL6610.40 / 1.434 100.60 / 0.310 10451 585 rev .lAns
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