# C since f x 0 in 5 5 the function is decreasing in

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(C) Sincef0(x)<0 in(0,5)(5,), the function is decreasingin those intervals.(D) Sincef0changes from positive to negative at 0,x=0 is thex-coordinate of a local maximum by the First Derivative Test.
Thusfis concave upward on the intervals(-,-5)(5,)(G) The function is concave downward on the intervals(-5,5).(H) The function has no inflection points since-5 and 5 are notin the domain off.(I)Theliney=0isahorizontalasymptotesincelimx→±4x2-25=0.(J) Since the denominator is zero whenx=±5, we compute thefollowing limits:limx→-5-
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2.(1 point) Suppose thatf(x) =8x-3ln(x),x>0.(A) List all critical numbers off. If there are no critical val-ues, enter ’NONE’.