7 1 1 4 2 1 3 4 7 4 1 1 2 4 1 3 28 1 8 3 29 5 x And 2 7 3 1 2 1 3 4 2 1 7 3 2 4

# 7 1 1 4 2 1 3 4 7 4 1 1 2 4 1 3 28 1 8 3 29 5 x and 2

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7 1 1 4 2 1 3 4 7 4 1 1 2 4 1 3 28 1 8 3 29 5 x       And
2 7 3 1 2 1 3 4 2 1 7 3 2 4 1 3 2 21 8 3 23 5 y       Then the solution is 29 23 , 5 5 . Check: Substitute the value 29 5 x   and 23 5 y in equation 2 7 x y and check as below: ? 2 7 29 23 2 7 5 5 58 23 7 5 7 7 x y The equation is true, then 29 23 , 5 5 is the solution for 2 7 x y Substitute the value 29 5 x   and 23 5 y in equation 3 4 1 x y and check as below:
? 3 4 1 29 23 3 4 1 5 5 87 92 1 5 1 1 x y The equation is true, then 29 23 , 5 5 is the solution for 3 4 1 x y Since, the ordered pair 29 23 , 5 5 satisfies both the equations. Then, the ordered pair 29 23 , 5 5 is the solution of the system of equations 2 7,3 4 1 x y x y Hence, the solution for the system of equations 2 7,3 4 1 x y x y is 29 23 , 5 5 . </EXPLANATION>

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