Therefore p a b 12 52 13 52 3 52 22 52 11 26 42 case

Info icon This preview shows pages 42–50. Sign up to view the full content.

View Full Document Right Arrow Icon
Therefore, P A B 12 52 13 52 3 52 22 52 11 26 42
Image of page 42

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
CASE 2 ( Countably Infinite Sample Space ): When is countably infinite, more care is required. Let   1 , 2 , 3 ,... where each j is a distinct value. Associated with each j is the probability p j P  j  , j 1,2, .... Of course, 0 p j 1 for all j . 43
Image of page 43
Because we can write   j 1 j , and the j are disjoint sets, P j 1 j  j 1 p j 1. With infinite , we cannot have equally likely outcomes (because the sum of the probabilities necessarily would be infinite). 44
Image of page 44

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon