Therefore p a b 12 52 13 52 3 52 22 52 11 26 42 case

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Therefore, P A B 12 52 13 52 3 52 22 52 11 26 42
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CASE 2 ( Countably Infinite Sample Space ): When is countably infinite, more care is required. Let   1 , 2 , 3 ,... where each j is a distinct value. Associated with each j is the probability p j P  j  , j 1,2, .... Of course, 0 p j 1 for all j . 43
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Because we can write   j 1 j , and the j are disjoint sets, P j 1 j  j 1 p j 1. With infinite , we cannot have equally likely outcomes (because the sum of the probabilities necessarily would be infinite). 44
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