95%(39)37 out of 39 people found this document helpful
This preview shows page 9 - 11 out of 11 pages.
(c) Suppose that Lis a line tangent to the boundary of the golf green and parallel to the path of the ball. Let Qbe thepoint where the line is tangent to the circle. Notice that there are two possible positions for Q. Find the possible x-coordinates of Q:smallest x-coordinate =-21.20 -21.2largest x-coordinate =21.20 21.2
10/31/2016hw02S2.110/117.2/4 points | Previous AnswersA Ferris wheel of radius 100 feet is rotating at a constant angular speed ωrad/sec counterclockwise. Using a stopwatch, therider finds it takes 4 seconds to go from the lowest point on the ride to a point Q, which is level with the top of a 44 ft pole.Assume the lowest point of the ride is 3 feet above ground level.Let Q(t)=(x(t),y(t))be the coordinates of the rider at time tseconds; i.e., the parametric equations. Assuming the rider beginsat the lowest point on the wheel, then the parametric equations will have the form: x(t)=rcos(ωt-π/2) and y(t)=rsin(ωt -π/2),where r,ωcan be determined from the information given. Provide answers below accurate to 3 decimal places. (Note: We haveimposed a coordinate system so that the center of the ferris wheel is the origin. There are other ways to impose coordinates,leading to different parametric equations.)(a) r= 100 100feet(b) ω= 0.628 0.235 rad/sec(c) During the first revolution of the wheel, find the times when the rider's height above the ground is 80 feet. first time =5.6 5.7 secsecond time=12.4 21 sec
10/31/2016hw02S2.111/118.3/3 points | Previous AnswersSCalcET7 10.1.033.Find parametric equations for the path of a particle that moves along the circle in the manner described.(Enter your answer as a comma-separated list of equations. Let xand ybe in terms of t.)(a) Once around clockwise, starting at (4, 2). $$x=4cos(t),y=2−4sin(t)(b) Two times around counterclockwise, starting at (4, 2). $$x=4cos(t),y=4sin(t)+2(c) Halfway around counterclockwise, starting at (0, 6). $$x=−4sin(t), y=4cos(t)+2Solution or ExplanationClick to View Solutionx2+ (y− 2)2= 160 ≤ t≤ 2π.0 ≤ t≤ 4π.0 ≤ t≤ π.