5 10 2 795 x 10 4 25 10 2 32 x 10\u00b2 c 70 10 3 80 10 4 70 08 x 10 3 62 x 10\u02c9 \u00b3 d

# 5 10 2 795 x 10 4 25 10 2 32 x 10² c 70 10 3 80 10 4

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79,500 ÷ (2.5 × 102) = (7.95 x 104) / (2.5 × 102) = 3.2 x 10²c.(7.0 × 10–3) – (8.0 × 10–4) = (7.0 – 0.8) x 10–3 = 6.2 x 10ˉ³d.(1.0 × 104) × (9.9 × 106) = (1.0 x 9.9) x 10¹º = 9.9 x 10¹º(Reference: Chang 1.31)4.What is the number of significant figures in each of the following measurements? (8 points)1
5.Express the results in the proper number of significant figures. (12 points)(Reference: Chang 1.35)6.Carry out the following conversions: (16 points)a.22.6 m to dm 22.6 m = 22.6 x 10¹ dm = 226 dmb.25.4 mg to kilograms 25.4 mg = 25.4 x 10ˉ6 kg = 2.54 x 10ˉ5kgc.556 mL to liters 556 mL = 556 x 10ˉ³ L = 5.56 x 10ˉ¹ Ld.10.6 kg/m3to g/cm³ 10.6 kg/m³ = 10.6 x (10³/106) g/cm³= 10.6 x 10ˉ³ g/cm³= 1.02 x 10ˉ² g/cm³ (Reference: Chang 1.39)7.The average speed of helium at 25°C is 1255 m/s. Convert this speed to miles per hour (mph). (4 points)(Reference: Chang 1.41)1255 m/s = (1255 / 1609.3) x (60 x 60) mph = 2807.43 mph = 2.807 x 10³ mph 2Copyright © 2014 by Thomas Edison State College. All rights reserved.

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• Spring '15
• Khurana
• Chemistry, Chemical substance, Chemical compound, Thomas Edison State College