2vr20 ma 174ma 26ma 3vr 30 ma 262ma 38ma 4vr 40 ma

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=2V/R:20 mA17.4mA2.6mA=3V/R: 30 mA26.2mA3.8mA=4V/R: 40 mA35.1mA4.9mA=5V/R: 50 mA 43.9mA6.1mA=6V/R: 60 mA52.8mA7.2mA=7V/R: 70 mA61.6mA8.4mATable 1: Determining Current for Ammeter CalibrationPart B: Series and Parallel Circuits
Circuit DiagramTheoreticalReqiMeasured(mA)iCorrected(mA)MeasuredReq% Difference1690Ω17.7 mA20.3 mA738.9Ω17%2207.6Ω75.5 mA83.9 mA178.78Ω-13.6%3307Ω48.1 mA54.2 mA276.75Ω-9.9%4384Ω38.8 mA43.7 mA343.25Ω-10.6%Table 2: Determining Resistance and % difference for Parallel and Series CircuitPart C: Light Bulb SystemsBulb SystemMeasured Resistance (Ω)A5.8 Ω B6.0 Ω C6.0 Ω A&B Series8.7 Ω A&B Parallel3.3 Ω Series Parallel3.7 Ω Table 3: Determining Resistance for Light Bulb SystemsAnalysis
The main calculations we used varied depending on which part of the experiment we were proceeding with. For part A, in which we calibrated the ammeter, we calculated the specific currents of the 100 Ω resistors and put the values into Ohm’s Law (Equation 1). We took the voltages given (0-7) and divided them by a resistance of 100Ω in order to get the theoretical current. For example, for the first row of the first column (Table 1), we had 0 for the voltage and our given resistance was 100Ω. Therefore the calculation would be 0V/100Ω= 0mA because V/R = I. The second column (A current of Table 2) the current was calculated by using the signal generator of the PASCO software. The third column was calculated by subtracting the measured current (Column 2 of Table 1)from the theoretical current (Column 1of Table 1). The full formula is given by Equation 5 in Table 1. For example for a theoretical current of 0mA with a voltage of 0 in which we found earlier, we measured a current of -0.2 mA on the PASCO software and our theoretical current was 0mA. Therefore, the calculation of A corrected (column 3 of Table 1), would be A corrected = theory current (mA)-A current (mA) (Equation5) or A corrected= 0 mA – (-0.2 mA). Hence the A corrected would be equal to 0 mA + 0.2 mA or 0.2 mA for the A corrected. For Part B, in which we calculated the resistances of different circuits (Table 2), we calculated the different equivalent resistances of the different circuits series (Diagram 1), parallel (Diagram 2), simple series parallel (Diagram 3), and complex series parallel (Diagram 4). The current measured (i measured) was given to us again by the PASCO software. In order to get the corrected current (i corrected), we used the information provided in the ammeter calibration data table (Table 1). Using thistable (Table 1), we identified the current that was measured in the ammeter calibration (shown in column 2 of Table 1) and added the corrected measure of that current (column 3 of Table 1)to the current we measured for the resistance summary table (Table 2). For example, our current for the series circuit (Diagram 1) measured to 17.7 mA. To get our corrected current for Table 2, we looked at the A current of Table 1 and found that the closest A current of Table one that is closest to 17.7 the i current wemeasured in table 2, is 17.4 mA. The A corrected for table 1 listed for 17.4 mA is 2.6 mA. To find the i

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