Membership n10015 px 1301 227 us women aged 20 and

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membership? N(100,15). P{X 130}=(1-NORM.DIST(130,100,15,TRUE))*100 =2.27 - U.S. women aged 20 and over have a mean HDL (good cholesterol) of 55 mg/dl with a standard deviation of 15.5 mg/dl. Assume the distribution is Normal . A) what % of women have 40mg/dl or less? =(NORM.DIST(40,55,15.5,TRUE))*100 B) what % have HDL levels of 60mg/dl or less? =(1NORM.DIST(60,55,15.5,TRUE))*100 C) what % are more than 40 mg/dl but less than 60 mg/dl? P(40<X<60) =(NORM.DIST(60,55,15.5,TRUE) NORM.DIST(40,55,15.5,TRUE))*100
- The heights of women aged 20-29 are approximately Normal with mean 64 inches and s.d. 2.7 inches. Men the same age have a mean height 69.3 inches and s.d. 2.8 inches . A) what is the z score for a woman 6 feet tall? 6 ft=6*12=72 inches Z=(72-64)/2.7=2.96 B) what is z score for a man 6 feet tall?Z =(72-69.3)/2.8=.96 Suppose the speeds of cars along a stretch of I-40 is normally distributed with a mean of 73
-Suppose the speeds of cars along a stretch of I-40 is normally distributed with a mean of 70 and standard deviation of 5 mph. A)
-for a certain population IQ-scores are approximately normally distributed with a mean of 96 points and sd of 15 points. A) B)

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