Determine the voltage across each diode in Figure 292 assuming the practical

# Determine the voltage across each diode in figure 292

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Problem 6: Determine the voltage across each diode in Figure 2–92, assuming the practical model. A)Reverse-Biased – IR = 5V/10= 0.5A, (I*R)+0.7 = (0.5*10)+0.7 = 5.7V / IR = 8V/10= 0.8A, (I*R)+0.7 = (0.8*10)+0.7 = 8.7V / V1-V2 = 5.7 - 8.7 = -3V – Both N and P are connected to a positive sourceand the N-side of the diode is higher in voltage than the P-side which leaks into the lower voltage side creating reverse-bias.B)Forward-Biased – The voltage is limited to 0.7V since the diode is forward-bias. The N-side of the diode is connected to the negative side of the source voltage and the P-side to the ground creating forward-bias
C)Forward-Biased – The voltage is limited to 0.7V since the diode is forward-bias. The P-side of the diode is connected to the positive side of the source voltage and the N-side to the ground creating forward-biasD)Forward-Biased – The voltage is limited to 0.7V since the diode is forward-bias. The P-side of the diode is connected to the positive side of the highest source voltage and the N-side to the ground creating forward-bias Problem 7: Determine the voltage across each diode in Figure 2–92, assuming an ideal diode. Problem 8:Determine the voltage across each diode in Figure 2–92, using the complete diode model with r′d=10Ωand r′d=100MΩ. Calculate total current from the source (answer: 6.18 mA). Find the current thru diode (Current division), find total voltage across the FB diode (answer: 0.73).d)Diode is FB by 20V source, replace it with rd'=10 ohms, but 10 << 10K, so you can ignore it (short). Write 2 loop equations and solve to find the current thru the diode (Answer 1mA). Find total voltage across the FB diode (answer: 0.71).