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22.8.2relevant interactionsLet’s look atφ3theory first, then the mass terms. We are interested in radiative corrections, so let’scoupleφto something else, say a fermionψ.We will set the mass ofφto zero for simplicity.TheLagrangian isL=−12φsquareφ+g3!φ3+λφψ¯ψ+ψ¯(i∂−M)ψ(22.59)22.8Super-renormalizable field theories259
Now consider the renormalization ofg. We can compute this by evaluating the 3-point function(0|T{φ(p)φ(q1)φ(q2)}|0)=g+(22.60)There is a radiative correction from the loop ofφ. This is UV finite, proportional tog3and not particu-larly interesting. A more important radiative correction comes from the loop of the fermion.M2=pq2kq1k−q1k+q2=λ3integraldisplayd4k(2π)4Tr[1k−M1k−q1−M1k+q2−M](22.61)=λ38π2Mintegraldisplay01dzintegraldisplay01−zdybracketleftBiggM2+p2(y+z−3yz−12)M2−p2yz+ 3logΛ2M2−p2yzbracketrightBigg(22.62)Takingp2= 0, this gives(0|T{φ(p)φ(q1)φ(q2)}|0)=g+λ316π2Mparenleftbigg1 + 3logΛ2M2parenrightbigg(22.63)So we find a (divergent) shift ingproportional to the mass of the fermionM. This is fine ifM∼g, butparametrically it’s really weird. AsMgets larger, the correction grows. That means that the theory issensitive to scales much larger than the scale associated withg. So,•Super-renormalizable theories are sensitive to UV physicsIs this a problem? Not in the technical sense, because the correction can be absorbed in a renormalizationofg. We just add a counterterm by writingg=gR−λ316π2Mparenleftbigg1 + 3logΛ2M2parenrightbigg(22.64)This will cancel the radiative correction exactly (atp= 0). Again, this is totally reasonable ifgR∼M, andtheoretically and experimentally consistent for allg, but ifgR≪Mitlooks strange.Will there be problems due to the quantum corrections? We can look at the Green’s function at a dif-ferent value ofp2. This would contribute to something like the scalar Coulomb potential. We find that of,course, the divergence cancels, and the result at smallpis something like(0|T{φ(p)φ(q1)φ(q2)}|0) ≈gR+λ316π2bracketleftbiggp2M+ 3Mlogparenleftbigg1−p2M2parenrightbigg+bracketrightbigg(22.65)≈gR+λ316π2p2M(22.66)So forp≪Mthese corrections are tiny and do in fact decouple asM→ ∞.As for the non-renormalizable case, we enjoy speculating that theultimate theory of natureis finite.ThenΛis physical. If we suppose that there is some baregwhich is fixed, then we need a very specialvalue ofΛto get the measured coupling to begR≪M. Of course, there is some solution forΛ, for anyg0andgR. But if we changeΛby just a little bit, then we getgR→gR+λ316π2MlogΛold2Λnew2(22.67)which is a huge correction ifM≫gR.