3/27/2019Lab 3 - Newton's Second Law: PreLab7/11Fnet2,y=$$m2g−FNPart (d)Consider the vertical motion of mass m1. In part (b), you wrote down the net force acting on the mass.This is the left hand side of the equation for Newton's Second Law (Fnet= ma) and this net force equalsm1a. Similarly, for the horizontal motion of mass m2the left hand side of the equation for Newton'sSecond Law is the net horizontal force and the right hand side is m2aBased on the above explanation and your answers in parts (b) and (c), what is the expression for theacceleration aof the two masses? Eliminate Tand give your answers in terms of m1, m2, g, and f. only.
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