# Find the true and estimated absolute errors in each

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Find the true and estimated absolute errors in each case. Solution We have f ( x ) = 2 x 3 - 3 x 2 - 11 x + 6 f ( x ) = 6 x 2 - 6 x - 11 Then x 0 = 1 f ( x 0 ) = - 6 f ( x 0 ) = - 11 x 1 = x 0 - f ( x 0 ) /f ( x 0 ) = 1 - ( - 6) / ( - 11) = 0 . 454545 | E t | = 0 . 045454 | E a | = 0 . 5454 f ( x 1 ) = 0 . 567994 f ( x 1 ) = - 12 . 48760 x 2 = 0 . 454545 - 0 . 567994 / ( - 12 . 48760) = 0 . 500030 | E t | = 0 . 000030 | E a | = 0 . 4548
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• Spring '10
• ROCKE
• Numerical Analysis, absolute errors, true absolute error, David M. Rocke

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