Return value if subprogram is a function 5 consider

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return value - if subprogram is a function 5. Consider the axioms of assignment, composition, and loop below: Assignment { P [E/V] } V := E { P } Composition { P } S 1 { Q } , { Q } S 2 { R } { P } S 1 ; S 2 { R } Loop { P&B } S { P } { P } while B loop S end loop { P& ¬ B } Prove the correctness of the following program segment. { n = j × (j + 1) / 2 & i 0 } while j ! = i loop j := j + 1; n := n + j; end loop { n = j × (j + 1) / 2 & i 0 & ¬ (j negationslash = i) } Show all steps used in the proof. Noting that the loop invariant I n = j × (j + 1) / 2 & i 0, we first apply the Loop rule { I & j negationslash = i } j := j + 1; n := n + j { I } { I } while j ! = i loop j := j + 1; n := n + j; end loop { I & ¬ (j negationslash = i) } (1)
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followed by the Composition rule. { I & j negationslash = i } j := j + 1 { P 1 } , { P 1 } n := n + j { I } { I & j negationslash = i } j := j + 1; n := n + j { I } (2) To determine P 1 , we apply the Assignment axiom. { n + j = j × (j + 1) / 2 & i 0 } n := n + j { n = j × (j + 1) / 2 & i 0 } (3) Therefore, P 1 n + j = j × (j + 1) / 2 & i 0. We apply the Assignment axiom again to prove { n + (j + 1) = (j + 1) × ((j + 1) + 1) / 2 & i 0 } j := j + 1 { n + j = j × (j + 1) / 2 & i 0 } (4) Note that n + (j + 1) = (j + 1) × ((j + 1) + 1) / 2 & i 0 n = j × (j + 1) / 2 & i 0 I. Since I & j negationslash = i I, the proof is complete. 6. Consider the Pascal array declaration: A : array [ 10 .. 10, 5 .. 5, 1 .. 10] of T; Assuming that T requires 10 bytes of storage and A is stored at relative location 100, what is the relative location of A [1, 1, 2]?
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