Write your final answer in the box a correct answer

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data on pages 5–7. Write your final answer in the box. A correct answer is worth full credit. If the answer is incorrect, your analysis of the spectra can be worth significant partial credit, so show your work clearly in the space below each set of data only. Answers outside of these places will be ignored . Final Structure Box (5) Mass spectrum : m/z = 178 (M; 100%), m/z = 179 (9.3%), and m/z = 180 (34.2%). No fluorine or iodine. Write formula(s) that are consistent with the mass spectrum in boxes. There may be more boxes than formulas. There may be more formulas than boxes. You may include, or not include (your choice) valid formulas that are eliminated by other means such as the IR or 1 H-NMR spectra.
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Chemistry 14C Winter 2011 Exam 2 Page 6 Page 6 score = (13) IR : 4000 cm -1 3500 cm -1 3000 cm -1 2500 cm -1 2000 cm -1 1500 cm -1 1000 cm -1 500 cm-1 1729 cm -1 IR workspace :
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Chemistry 14C Winter 2011 Exam 2 Page 7 Page 7 score = Anything written outside the boxes on this page will be ignored. Write only 1 H-NMR implications and 13 C-NMR conclusions in these boxes. (12) 1 H-NMR : Chemical shift Splitting Integral Implications 9.52 ppm singlet 1 5.46 ppm singlet 2 3.37 ppm triplet 2 1.56 ppm triplet 2 1.51 ppm pentet 2 1.26 ppm singlet 6 (2) 13 C-NMR : 206.4 ppm (doublet), 69.8 ppm (triplet), 51.1 ppm (singlet), 48.2 ppm (triplet), 34.7 ppm (triplet), 23.7 ppm (triplet), and 22.3 ppm (quartet). 13 C-NMR conclusions :
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  • Spring '06
  • Scerri
  • Chemistry, ppm, base peak

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