And mos formed by the side to side overlap of p

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and MOs formed by the side-to-side overlap of p orbitals are called . A superscript star (*) is used to designate an antibonding MO. To write the electron configuration of F 2 + , determine the number of valence electrons and write the sequence of MO energy levels, following the sequence order given in the text. 11-11
Solution: a) A is the * 2 p molecular orbital (two p orbitals overlapping side to side with a node between them); B is the 2 p molecular orbital (two p orbitals overlapping end to end with no node); C is the 2 p molecular orbital (two p orbitals overlapping side to side with no node); D is the * 2 p molecular orbital (two p orbitals overlapping end to end with a node). b) F 2 + has thirteen valence electrons: [2 x F(7e ) – 1 (from + charge)]. The MO electron configuration is ( 2 s ) 2 ( * 2 s ) 2 ( 2 p ) 2 ( 2 p ) 2 ( 2 p ) 2 ( * 2 p ) 2 ( * 2 p ) 1 . The * 2 p molecular orbital, A, 2 p molecular orbital, B, and 2 p molecular orbital, C, are all occupied by at least one electron. The * 2 p molecular orbital is unoccupied. c) A * 2 p molecular orbital, A, has only one electron. 11.33 a) A is the * 2 p molecular orbital; B is the 2 p molecular orbital; C is the 2 p molecular orbital; D is the * 2 p molecular orbital; E is the 2 s molecular orbital; F is the * 2 s molecular orbital. b) The * 2 p molecular orbital, D, is the highest in energy. c) The 2 s molecular orbital, E, is the lowest in energy. d) 2 s < * 2 s < 2 p < 2 p < * 2 p < * 2 p (E < F < C < B < A < D) 11.34 Plan: To write the electron configuration of Be 2 + , determine the number of electrons and write the sequence of MO energy levels, following the sequence order given in the text. Bond order = ½[(no. of electrons in bonding MO) – (no. of electrons in antibonding MO)]. Recall that a diamagnetic substance has no unpaired electrons. . 2 . * 2 1 )
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