1 n 1 cos 2 n \u03c0 n \u03c02 n 1 2 n 3 n 2 3 3 n 2 1 n log 5 n 4 n 1 1 n n 5 n 1 cos n\u03c0

# 1 n 1 cos 2 n π n π2 n 1 2 n 3 n 2 3 3 n 2 1 n log

• Homework Help
• 4
• 87% (15) 13 out of 15 people found this document helpful

This preview shows page 3 - 4 out of 4 pages.

1. n = 1 cos 2 ( n π ) n π 2. n = 1 ( 2 n + 3 ) ! ( n ! ) 2 3
3. n = 2 1 n log ( 5 + n ) 4. n = 1 1 n n 5. n = 1 cos ( n π ) n π 6. n = 1 6 + sin ( n ) n Correct Answers: CE CJ CK AE BD CG 15. (1 pt) (a) Check all of the following that are true for the series n = 1 3 n 2 n - 1 A. This series converges B. This series diverges C. The integral test can be used to determine conver- gence of this series. D. The comparison test can be used to determine con- vergence of this series. E. The limit comparison test can be used to determine convergence of this series. F. The ratio test can be used to determine convergence of this series. G. The alternating series test can be used to determine convergence of this series. (b) Check all of the following that are true for the series n = 1 ln ( 2 n )+ 3 n n 2 A. This series converges B. This series diverges C. The integral test can be used to determine conver- gence of this series. D. The comparison test can be used to determine con- vergence of this series. E. The limit comparison test can be used to determine convergence of this series. F. The ratio test can be used to determine convergence of this series. G. The alternating series test can be used to determine convergence of this series. Correct Answers: BDEF BCDE Generated by c WeBWorK, , Mathematical Association of America 4
• • • 