8.00E-041.00E-030.00E+005.00E+071.00E+081.50E+082.00E+082.50E+08f(x) = 82938206664.63x + 100801501.44Stress Vs. StrainStrain (mm)Stress (N/m^2)IV.DiscussionWhen the elastic limit is not exceeded, the deformation is recoverable socomparing both cases of increasing and decreasing the hanging weights, thestrain should be the same for the same stress. That is the Young’s Modulusshould be the same for both cases. Do you observe this?The graphs demonstrate that the Young’s Modulus is the inverse of the othergraph. Graph 1 has positive young’s modulus while graph 2 has a negative valuebecause of the order and declining values in each case.
In your plot, how well do the data points fall in a straight line? What wouldbe the factors that cause the deviation from the straight line?The data points don’t all fall in a straight lineThe plots don’t fall directly on the straight line, this deviation may be caused byhuman error or a systematic error and bad calibration of the instruments used inthe lab. If the wire in your apparatus is replaced with one twice as thick, which of thefollowing would change when you add the first kilogram, and how: ∆ L,F,Stress, Strain and value of Young’s Modulus. The stress will be 4times smaller and the young’s modulus will consequently besmaller as well.
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