Lab 8 - Conservation of Mechanical Energy.docx

Finally this procedure is repeated until the total

This preview shows page 1 - 3 out of 3 pages.

Finally, this procedure is repeated until the total distance between the photogate and glider is only 10cm. We compute the kinetic energy acquired as well as the potential energy lost at each sliding distance and tabulate the data and include error for the slope of the graph. Results and Analysis Table 1: Raw Data Trial Number x (m) Speed (m/s) Δ K ( 1 2 Mv 2 + 1 2 mv 2 ) - Δ U (mgx) 1 1.0 1.355 220.231 196.2 2 1.0 1.350 218.609 196.2 3 1.0 1.354 219.906 196.2 4 1.0 1.353 219.582 196.5 5 1.0 1.353 219.582 196.2 1 0.9 1.285 198.064 176.6 2 0.9 1.281 196.833 176.6 3 0.9 1.282 197.141 176.6 4 0.9 1.285 198.064 176.6 5 0.9 1.287 198.682 176.6 1 0.8 1.215 177.073 156.96 2 0.8 1.218 177.949 156.96 3 0.8 1.216 177.365 156.96 4 0.8 1.216 177.365 156.96 5 0.8 1.218 177.949 156.96
Image of page 1

Subscribe to view the full document.

1 0.7 1.143 156.709 137.3 2 0.7 1.140 155.887 137.3 3 0.7 1.144 156.983 137.3 4 0.7 1.141 156.161 137.3 5 0.7 1.143 156.709 137.3 1 0.6 1.065 136.050 117.7 2 0.6 1.064 135.795 117.7 3 0.6 1.065 136.050 117.7 4 0.6 1.067 136.562 117.7 5 0.6 1.068 136.818 117.7 1 0.5 0.981 115.435 98.1 2 0.5 0.984 116.142 98.1 3 0.5 0.982 115.671 98.1 4 0.5 0.984 116.142 98.1 5 0.5 0.985 116.379 98.1 1 0.4 0.889 94.799 78.5 2 0.4 0.889 94.799 78.5 3 0.4 0.890 95.012 78.5 4 0.4 0.891 95.226 78.5 5 0.4 0.889 94.799 78.5 1 0.3 0.787 74.293 58.9 2 0.3 0.788 74.482 58.9 3 0.3 0.787 74.293 58.9 4 0.3 0.787 74.293 58.9 5 0.3 0.788 74.482 58.9 1 0.2 0.667 53.644 39.2 2 0.2 0.665 53.045 39.2 3 0.2 0.664 52.885 39.2 4 0.2 0.665 53.045 39.2 5 0.2 0.666 53.205 39.2 1 0.1 0.521 32.559 19.6 2 0.1 0.518 32.185 19.6 3 0.1 0.520 32.434 19.6 4 0.1 0.522 32.684 19.6 5 0.1 0.519 32.310 19.6 Using columns 4 and 5 of table 1 we place all the ( ΔK, -ΔU) experimental points on a scatter plot (Fig. 3) and perform linear regression. Visually those data points fall more or less on a straight line which is supported by 1 – R 2 = 1 – 0.9999 = 0.0004 < 1. However, since the intercept is B = 10.93 ± 0.1468, the predicted straight line does not go through the origin within error margin unlike what is expected which can be accounted for by the errors talked about in the discussion.
Image of page 2
Figure 3: Linear regression graph of Δ K vs - Δ U for different sliding distances Matching the slope of Eq. (1) with the slope A = 0.9682 ± 0.0012 of the trendline, we find Δ K =− ΔU → Δ K ΔU = 1 fractionaldiscrepancy = | 0.9682 1 | 1 = 0.0318 Discussion
Image of page 3

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern