C 005 0002 atomic 0048 atomic n but we need it in

Info icon This preview shows pages 18–20. Sign up to view the full content.

View Full Document Right Arrow Icon
c = 0.05 – 0.002 atomic % = 0.048 atomic % N But, we need it in atoms/cm3: Lattice paramater of BCC Fe = 0.2866 nm For BCC there are 2 atoms per cell Therefore we get 0.85 x 10 23 Fe atoms/cm 3 Now we have already calculated the fractional change in composition of N: 0.00048 x 0.85 x 10 23 = 4.08 x 10 19 N atoms/cm 3 = c
Image of page 18

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
C/ x = 4.08 x 10 19 N atoms/cm 3 0.05 cm = 8.16 x 10 20 N atoms/cm 4 J 973 = - (3.64 x 10 -7 cm 2 /sec) (8.16 x 10 20 N atoms/cm 4 ) = -2.97 x 10 14 N atoms/cm 2 sec
Image of page 19
Now we have to account for the flux through the total surface area. Area of surface = 4 π r 2 = 50.26 cm 2 Time = 3600 sec So, in one hour (multiply flux by area by time): = 5.37 x 10 19 N atoms 1 mole of N = 6.02 x 10 23 N = 14 g N 5.37 x 1019 N atoms 6.02 x 1023 N x 14 g = 1.25 x 10 -3 g
Image of page 20
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern