a 73 17 43 2 mol 2 mol 2 x 525 105 g of NH4Cl b Gas remain 23 mol of

# A 73 17 43 2 mol 2 mol 2 x 525 105 g of nh4cl b gas

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a.(73 / 17) = 4.3 mol + (73 / 36.5) = 2 mol 2 mol = (2 x 52.5) = 105 g of NH4Clb.Gas remain: 2.3 mol of NH3c.T = 14 + 273 = 287oKd.P = 752 mmHg = 0.99 atme.V = nRT / P = (2.3 x 0.082 x 287) / 0.99 = 54.7 L(Reference: Chang 5.59)10.A mixture of gases contains 0.31 mol CH4, 0.25 mol C2H6,and 0.29 mol C3H8. The total pressure is 1.50 atm. Calculate the partial pressures of the gases. (8 points)(Reference: Chang 5.67)11.Propane (C3H8) burns in oxygen to produce carbon dioxide gas and water vapor. 38222C H5O3CO4H O7.45g(Reference: Chang 5.109)4Copyright © 2017 by Thomas Edison State University. All rights reserved. 12.A 10.0 g piece of pure aluminum is placed in 75.0 mL of 0.54 M hydrochloric acid at STP condition. They react as follows:2Al + 6HCl 3H2(g) + 2AlCl3Calculate the following: i.232Al6HCl3H (g)2AlCl10.0g75.0mL0.37mol0.54Mii.32n0.54x75.0x104.05x10molof HCl produce22.03x10mol of 2Ha.Hydrogen gas produced : V = nRT / P = (2.03 x 10-2 x 0.082 x 273) /1 = 0.45 Lb.Al+3 produced n = (4.05 x 10-2) / 3 = 1.35 x 10-2 mol M = (1.35 x 10-2) / (75.0 x 10-3) = 0.18 mol /Lc.Cl– produced n = 4.05 x 10-2 mold.M = (4.05 x 10-2) / (75.0 x 10-3) = 0.54 mol / L5Copyright © 2017 by Thomas Edison State University. All rights reserved. #### You've reached the end of your free preview.

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• Winter '20
• Written Assignment, Thomas Edison State University
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