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57. What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2in 43.88 mL of a 0.3842 M solution of Cu(NO3)2?32322CuNO4KI 2CuI I4KNOSolutionUse molarity to convert. This solution involves the following steps:1. Converting the volume of KI to moles of KI2. Converting the moles of KI to moles of Cu(NO3)23. Converting the moles of32K Cu(NO )to a volume of KI.Cu(NO3)2solution320.3842 mol Cu(NO )1 L43.88 mL 1000 mL4 mol KI1 L322 mol Cu(NO )1 L KI0.2089 mol KI= 161.4 mLAll of these steps can be shown together, as follows:3232323243.88 mL Cu(NO)0.3842 mol Cu(NO)4 mol KI1000 mL KI11000 mL Cu(NO)2 mol Cu(NO)0.2089 mol KI= 161.40 mL KI solution58. A mordant is a substance that combines with a dye to produce a stable fixed color in a dyed fabric. Calcium acetate is used as a mordant. It is prepared by the reaction of acetic acid with calcium hydroxide.32322222CH CO H Ca OHCa CH CO2OHWhat mass of Ca(OH)2is required to react with the acetic acid in 25.0 mL of a solution having a density of 1.065 g/mL and containing 58.0% acetic acid by mass?SolutionPage 9 of 10
OpenStax Chemistry4.3: Reaction Stoichiometry22Volume of solution mass solution mass acetic acid moles of acetic acid moles Ca(OH)mass Ca(OH)The last step is to determine the mass of Ca(OH)2from the moles:1.065 g solution25.0 mL 58.0 g aceticacid1 mL100 g solution323321 mol CH COOH1 mol Ca(OH)60.05 g CHCOOH2 mol CH COOH74.093 g Ca(OH)9.53 g1 mol59. The toxic pigment called white lead, Pb3(OH)2(CO3)2, has been replaced in white paints by rutile, TiO2. How much rutile (g) can be prepared from 379 g of an ore that contains 88.3% ilmenite (FeTiO3) by mass?323222FeTiO4HCl Cl2FeCl2TiO2OHSolutionFind from worked example, check your learning problemmass of ilmenite = 379 g ore30.883 g FeTiO1 g ore3= 334.6 g FeTiO3mass of rutile = 334.6 g FeTiO31 mol FeTiO3151.7 g FeTiO22 mol TiO32 mol FeTiO2279.88 g TiO1 mol TiO2= 176 g TiOThis resource file is copyright 2015, Rice University. All Rights Reserved.Page 10 of 10