Is easily understood second most of the volatile

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is easily understoodSecond: most of the volatile elements would have been lost during the high-temperature phase following the impact, explaining the lack of these materials on the Moon. by making the Moon primarily of terrestrial mantle material, it is also possible to understand similarities such as identical abundances of various oxygen isotopes.
Crash Course: The Moonhttps://
9.5 – Mercury (Orbit)Mercury:Has no atmosphereSurface is heavily crateredthe nearest planet to the Sunthe shortest period of revolution about the Sun (88 of our days)highest average orbital speed (48 km/s)The semimajor axis of its orbit—that is, the planet’s average distance from the Sun—is 58 million kilometers, or 0.39 AUHowever, because its orbit has the high eccentricity of 0.206, Mercury’s actual distance from the Sun varies from 46 million kilometers at perihelion to 70 million kilometers at aphelion
9.5 – Mercury (Composition & Structure)Mercury:mass is 1/18th that of Earth → the smallest terrestrial planetdiameter of 4878 kilometersless than half of Earth density is 5.4 g/cm3
9.5 – Mercury (Composition & Structure)Mercury’s composition: its high density tells us that it must be composed largely of heavier materials such as metalsThe most likely models for Mercury’s interior suggest a metallic iron-nickel core amounting to 60% of the total mass, with the rest of the planet made up primarily of silicatesThe core has a diameter of 3500 kilometers and extends out to within 700 kilometers of the surfaceweak magnetic fieldThe existence of this field is consistent with the presence of a large metal core, and it suggests that at least part of the core must be liquid in order to generate the observed magnetic field
Mercury’s Internal StructureThe interior of Mercury is dominated by a metallic core about the same size as our Moon.
Density of the MoonLet’s find the density of Moon if its mass is 7.35 × 1022 kg and its diameter is 3476 km. Know: mass = 7.35 × 1022 kg, radius = 1738 km = 1738 x 103m = 1.74 x 106mWant to find: densityFormulas:V = πR3Density =
Density of the MoonLet’s find the density of Mercury if its mass is 7.35 × 1022 kg and its diameter is 4878 km. Let’s find volume. Plug in the number in the formula.V = π(1.74 x 106m)3V = 2.20 x 1019m3
Density of the MoonLet’s find the density of Mercury if its mass is 7.35 × 1022 kg and its diameter is 4878 km. Let’s find density. Plug in the number in the formula.Density = Density = 3.33 x 103kg/m3
Density of Mercury ProblemLet’s find the density of Mercury if its mass is 7.35 × 1022 kg and its diameter is 4878 km. Formulas:V = πR3Density =
Density of MercuryLet’s find the density of Mercury if its mass is 7.35 × 1022 kg and its diameter is 4878 km. Know: mass = 3.3 × 1023 kg, radius = 2439 km = 2439 x 103m = 2.44 x 106mWant to find: densityFormulas:V = πR3Density =
Density of the MoonLet’s find the density of Mercury if its mass is 7.35 × 1022 kg and its diameter is 4878 km.

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Term
Fall
Professor
Robbins
Tags
Impact crater

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