Did you notice any discrepancies between the graphs you made and the

Did you notice any discrepancies between the graphs

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1.Did you notice any discrepancies between the graphs you made and the predictions of Equations (2) and (3)? If so, are your graphs in better agreement with the predictions of the “better” theory – Equations (5) and (6)?2.Under what circumstances would the “better” theory be unnecessary to explain your experimental results? Under what circumstances would it be essential? (Hint: consider you experimental uncertainties)3.In part A why is it best to gather data over a range in which the value of a varies by a substantial amount?4.How reasonable do you think it is to suppose that the frictional force in the pulley, f, is the same in all runs? How about its effective mass, mp5.Can you think of any complications (either physical or computational) that are introducedby mounting the laser-gate tabs on the pulley??
Calculations:Part A:Net Force of SamplesSampleNet Force=(m1m2)g1(97.99g56.81g)(980cm/s2)=40,356.4gcm/s22(95.99g58.81g)(980cm/s2)=36,436.4gcm/s23(93.99g60.81g)(980cm/s2)=32,516.4gcm/s24(91.99g62.81g)(980cm/s2)=28,596.4gcm/s25(89.99g64.81g)(980cm/s2)=24,676.4gcm/s26(87.99g66.81g)(980cm/s2)=20,756.4gcm/s27(85.99g68.81g)(980cm/s2)=16,836.4gcm/s28(83.99g70.81g)(980cm/s2)=12,916.4gcm/s29(81.99g72.81g)(980cm/s2)=8,996.4gcm/s2Effective Mass of the PulleySlope=m1+m2+mp183.43g=154.8g+mpmp=¿28.63 ± .92 gPart C – Predicted Total Mass Differenceg=980cm/s2m1+m2=114.8gmp=28.63ga=60cm/s2m(¿¿1m2)g=(m1+m2+mp)a¿m(¿¿1m2)(980cm/s2)=(114.8g+28.63g)(60cm/s2)¿m1m2=8.78gPredicted Difference in Added Massm(¿¿a1+mc1)−(ma2+mc2)m1m2=¿m(¿¿a1+7.99g)−(ma2+6.81g)8.78=¿ma1ma2=7.6g≈8gPercent Error¿theorectical valueexperimental valure¿theorectical value×100error=¿
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