1202352174 c find the median of the raw data in

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Blueprint Reading for Welders
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Chapter 5 / Exercise 13
Blueprint Reading for Welders
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10+9+6+2+5+3+9+1+6+3+10+4+7+6+3+5+6+2+6+5+3+7+2=120 120/23=5.2174 c. Find the median of the raw data . In order to find the median, I rearranged all the numbers/values from least to greatest and use the number in the middle as the average. 1, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6, 6, 6, 6, 7, 7, 9, 9, 10, 10 The median is 6
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Blueprint Reading for Welders
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Chapter 5 / Exercise 13
Blueprint Reading for Welders
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4 Module 2 – Measures of Central Tendency 6. The chart below represents the number of inches of snow for a seven-day period. Sunday Monday Tuesday Wednesday Thursday Friday Saturday 2 5 3 10 0 4 2 a. Find the mean, median, and mode. Mean : 2+5+3+10+0+4+2=26 26/7=3.7143 Median : 0, 2, 2, 3, 4, 5, 10 = 3 Mode : 2 b. Which is the best measure of central tendency? The median would be the best measure of central tendency because there is an outlier in the values. The outlier is ‘10’ and it skews the data. c. Remove Wednesday from the calculations. How does that impact the three measures of central tendency? Mean : 2+5+3+0+4+2=16 16/6=2.667 Median : 0, 2, 2, 3, 4, 5 =2.5 Mode : 2 By removing Wednesday’s data, we’re removing the outlier in the group and it changed the mean drastically and it also reduced the median by .5. d. Describe the effect outliers have on the measures of central tendency. The outlier of 10 from Wednesday’s data skewed the average for the mean. This made all of the variables higher and once removed, the other measures of central tendency were affected. The outlier typically doesn’t have a drastic effect on the median or the mode but it does on the mean. 7. A dealership sold 15 cars last month. The purchase price of the cars, rounded to the nearest thousand, is represented in the table. Purchase Price Number of cars sold $15,000 3 $20,000 4 $23,000 5 $25,000 2 $45,000 1
5 Module 2 – Measures of Central Tendency a. Find the mean and median of the data. Mean : $15,000+$15,000+$15,000+$20,000+$20,000+$20,000+$20,000+$23,000+ $23,000+ $23,000+$23,000+$23,000+$25,000+$25,000+$45,000=$335,000 $335,000/15 = $22,333 Median : $23,000 Mode : $23,000 b. Which measure best represents the data? Use the results to support your answer. I would say that any of the measures would best represent the data. There’s not a specific one that stands out since they all represent the data appropriately. All of the variables are very close in value and there’s not a drastic value difference in the results.

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