William is hemophilic and must be xhy linda a carrier

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Linda’s genotypes. William is hemophilic and must be XhY. Linda, a carrier, isheterozygous, so she must be XHXh. Crossing XhY and XHXh results in 50% ofsons that are XHY and do not have the condition, and 50% that are XhY and dohave the condition.
Question 7If William and Linda have a daughter, what is the probability that she will havethis condition?
Question 8In humans, how many alleles of genes found on the X chromosome do malehave?
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9/21/2016Human Inheritance Quiz4/4Points: 10 out of 10Question 9According to the pedigree below, this trait is ____________________.
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