Linda’s genotypes. William is hemophilic and must be XhY. Linda, a carrier, isheterozygous, so she must be XHXh. Crossing XhY and XHXh results in 50% ofsons that are XHY and do not have the condition, and 50% that are XhY and dohave the condition.
Question 7If William and Linda have a daughter, what is the probability that she will havethis condition?
Question 8In humans, how many alleles of genes found on the X chromosome do malehave?