CHEM
Lab 9.docx

10 5 798 10 4 598 10 4 42267 solution 5 fe3 scn

• Lab Report
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10 5 ] [ 7.98 10 4 ][ 5.98 10 4 ] =422.67 Solution 5 Fe3+ SCN- FeSCN2+

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Initial Concentration (M) 0.001 0.001 0 Change in Equilibrium(M) -28.3185*10^-5 -28.3185*10^-5 28.3185*10^-5 Equilibrium Concentration(M) 7.17*10^-4 7.17*10^-4 28.3185*10^-5 K c = [ 28.3185 10 5 ] [ 7.17 10 4 ][ 7.17 10 4 ] =550.848 The average value of Kc: (550.848+422.67+556.6+538.105+678.241)/5=549.293 The standard deviation of all 5 Kc values is ~90.61, so the range would 458.683<Kc<639.903, which means that Solution 5, Solution 3, and Solution 2 are within this range.
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• Fall '06
• Goddfried
• Chemistry, Potassium Thiocyanate

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