Separation and Confirmatory Test Mercuric chloride test We have to reduce the

Separation and confirmatory test mercuric chloride

This preview shows page 31 out of 31 pages.

Separation and Confirmatory Test Mercuric chloride test: We have to reduce the Sn 4+ to Sn 2+ using iron wire in acid medium. Then HgCl 2 oxidizes Sn 2+ to Sn 4+ and being reduced according to the amount of HgCl 2 used. The test may give white ppt. (HgCl 2 ) or gray ppt. (Hg 2 Cl 2 + Hg o ) or finally black ppt. (Hg o ) (oxidation-reduction reaction). Sn 4+ + Fe° + H + Sn 2+ + Fe 2+ (iron wire/H + ) white Sn 2+ + HgCl 2 Hg 2 Cl 2 + [SnCl 6 ] 2- white Hg 2 Cl 2 + xxs HgCl 2 Hg o + [SnCl 6 ] 2- Black 4- Test for stannic in presence of Sb 3+ We have to boil with iron wire (Fe°) in acid medium for two reasons; Sb 3+ + 3 Fe o 𝑯 + Sb o + 3 Fe 2+ removed by fi itration Sn 4+ + 3 Fe o 𝑯 + Sn 2+ + 2 Fe 2+
Image of page 31

You've reached the end of your free preview.

Want to read all 31 pages?

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture

  • Left Quote Icon

    Student Picture

Stuck? We have tutors online 24/7 who can help you get unstuck.
A+ icon
Ask Expert Tutors You can ask You can ask You can ask (will expire )
Answers in as fast as 15 minutes