A physics student places an object 60 cm from a

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A physics student places an object 6.0 cm from a converging lens of focal length 9.0 cm. What is the magnitude of the magnification
of the image produced? 1. | M | = 0 . 6
hatch (heh595) – reflection refraction imaging HW – yeazell – (55740) 9 The magnitude of the magnification is thus | M | = vextendsingle vextendsingle vextendsingle vextendsingle q p vextendsingle vextendsingle vextendsingle vextendsingle = 18 . 0 cm 6 . 0 cm = 3 . 0 . 027 10.0 points An ordinary magnifying glass produces an image which is 1. real and inverted 2. none of these 3. virtual and inverted 4. real and erect 5. virtual and erect correct Explanation: A magnifying glass is a double convex lens. The object is located just inside the focal length. Thus the image is virtual, erect, and the magnification is larger than 1. 028 (part 1 of 3) 10.0 points A diverging lens has a focal length of 15 . 8 cm. 2 f 2 f f f Locate the image for object distance of 35 . 9 cm . = - 7 . 87492 cm . The magnification is M = - q p = - - 7 . 87492 cm 15 . 7 cm = 0 . 501587 . The image is virtual, upright and 7 . 87492 cm in front of the lens. f q = fp p - f = - (15 . 8 cm) (35 . 9 cm) 35 . 9 cm - ( - 15 . 8 cm) = - 10 . 9714 cm . The magnification is M = - q p = - - 10 . 9714 cm 35 . 9 cm = 0 . 305609 . The image is virtual, upright and 10 . 9714 cm in front of the lens. 029 (part 2 of 3) 10.0 points Find the image distance for an object distance of 15 . 7 cm . Correct answer: - 7 . 87492 cm. Explanation: Let : p = 15 . 7 cm . q = - (15 . 8 cm) 15 . 7 cm 15 . 7 cm - ( - 15 . 8 cm)
hatch (heh595) – reflection refraction imaging HW – yeazell – (55740) 10 The magnification is M = - q p = - - 5 . 35481 cm 8 . 1 cm = 0 . 661088 . The image is virtual, upright and 5 . 35481 cm in front of the lens. 031 (part 1 of 4) 10.0 points An object is placed 10 m before a convex lens with focal length 6 . 4 m . Another convex lens is placed 29 . 8 m behind the first lens with a focal length 5 . 9 m (see the figure below). Note: Make a ray diagram sketch in order to check your numerical answer.
Explanation: Basic Concept:

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