−
(
y
3
)
2
= (
x
3
+
Now we use the sum of two cubes formula for the first factor and the difference of two cubes formula for the second factor.
x
3
+
y
3
=
(
x
+
y
)(
x
2
x
3
−
y
3
=
(
x
−
y
)(
x
2
Hence,
x
6
−
y
6
=
(
x
+
y
)(
x
2
−
xy
+
y
2
)
Student Practice 12
Factor. 64
a
6
−
1
A-34A-35
Page 24 of 32
Print | Beginning & Intermediate Algebra
1/31/2014
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