A1315 a z test of p h p 104320425000 245 h 1 p 245 n

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A13.15 a z-test of p : H 0 p = 104,320/425,000 = .245 : H 1 p > .245 n ) p 1 ( p p p ˆ z = 1 2 3 4 5 6 7 8 9 10 11 A B C D z-Test: Proportion Deliver Sample Proportion 0.2825 Observations 400 Hypothesized Proportion 0.245 z Stat 1.74 P(Z<=z) one-tail 0.0406 z Critical one-tail 1.6449 P(Z<=z) two-tail 0.0812 z Critical two-tail 1.9600 z = 1.74, p-value = .0406. There is enough evidence to indicate that the campaign will increase home delivery sales. b z-test of p : H 0 p = 110,000/425,000 = .259 : H 1 p > .259
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342 This edition is intended for use outside of the U.S. only, with content that may be different from the U.S. Edition. This may not be resold, copied, or distributed without the prior consent of the publisher. n ) p 1 ( p p p ˆ z = 1 2 3 4 5 6 7 8 9 10 11 A B C D z-Test: Proportion Deliver Sample Proportion 0.2825 Observations 400 Hypothesized Proportion 0.259 z Stat 1.07 P(Z<=z) one-tail 0.1417 z Critical one-tail 1.6449 P(Z<=z) two-tail 0.2834 z Critical two-tail 1.9600 z = 1.07, p-value = .1417. There is not enough evidence to conclude that the campaign will be successful. A13.16 t-tests of D μ a D 0 : H μ = 40 D 1 : H μ > 40 D D D D n / s x t μ = 1 2 3 4 5 6 7 8 9 10 11 12 13 14 A B C t-Test: Paired Two Sample for Means SAT after SAT before Mean 1235 1162 Variance 37970 28844 Observations 40 40 Pearson Correlation 0.94 Hypothesized Mean Difference 40 df 39 t Stat 2.98 P(T<=t) one-tail 0.0024 t Critical one-tail 1.6849 P(T<=t) two-tail 0.0049 t Critical two-tail 2.0227 t = 2.98, p-value = .0024. There is enough evidence to conclude that the ETS claim is false. b D 0 : H μ = 110 D 1 : H μ < 110 D D D D n / s x t μ =
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343 This edition is intended for use outside of the U.S. only, with content that may be different from the U.S. Edition. This may not be resold, copied, or distributed without the prior consent of the publisher. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 A B C t-Test: Paired Two Sample for Means SAT after SAT before Mean 1235 1162 Variance 37970 28844 Observations 40 40 Pearson Correlation 0.94 Hypothesized Mean Difference 110 df 39 t Stat -3.39 P(T<=t) one-tail 0.0008 t Critical one-tail 1.6849 P(T<=t) two-tail 0.0016 t Critical two-tail 2.0227 t = –3.39, p-value = .0008. There is enough evidence to conclude that the Kaplan claim is also false. A13.17a t-test of μ 000 , 1 : H 000 , 1 : H 1 0 < μ = μ n / s x t μ = 1 2 3 4 5 6 7 8 9 10 11 12 A B C D t-Test: Mean Potatoes Mean 985.3 Standard Deviation 49.2 Hypothesized Mean 1000 df 49 t Stat -2.11 P(T<=t) one-tail 0.0198 t Critical one-tail 1.6766 P(T<=t) two-tail 0.0396 t Critical two-tail 2.0096 T = 2.11; p - value = .0198. There is enough evidence to infer that the supplier is cheating him. b t-estimator of μ n s t x 2 / α ±
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