The events are not mutually exclusive Rolling 3 2 is an outcome in event A and

The events are not mutually exclusive rolling 3 2 is

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The events are not mutually exclusive. Rolling 3, 2 is an outcome in event Aand also an outcome in event B. The events are mutually exclusive. Rolling 4, 6 is an outcome in event Abut not in event B.The events are mutually exclusive. Rolling 3, 2 is an outcome in event Aand also an outcome in event B.Are Aand Bindependent events? Explain your answer.Incorrect. While the rolls of two dice are independent events, the events Aand Bare specific outcomes of the rolls incombination.Events Aand Bare dependent because they have outcomes in common.Events Aand Bare independent because they are mutually exclusive. Events Aand Bare dependent because the probability of event Ahappening is affected by whether event Bhashappened.Events Aand Bare independent because the roll of one die has no effect on the outcome of rolling a second die.
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3/9/17, 7(28 PMHmwk: Chapter 3Page 3 of 92.1.5/2 points | Previous AnswersIllowskyIntroStat1 3.HW.090.Consider the following scenario:Let P(C) = 0.5Let P(D) = 0.6Let P(C| D) = 0.7Part (a)Part (b)Part (c)Part (d)Additional MaterialsSection 3.1Find P(C AND D).0.42 0.42Are Cand Dmutually exclusive? Why or why not?Correct! If two events are mutually exclusive, the probability of them occurring together is zero.There is not enough information to determine if Cand Dare mutually exclusive.Cand Dare not mutually exclusive because . Cand Dare mutually exclusive because they have different probabilities.Cand Dare not mutually exclusive because .P(C) + P(D) 1P(CANDD) 0Are Cand Dindependent events? Why or why not?Correct! Calculating does not result in .The events are not independent because .The events are independent because they are mutually exclusive. The events are not independent because .The events are not independent because the sum of the events is less than 1.P(C) ×P(D) P(C| D)P(C| D) P(C)P(C| D)P(C)Find P(D| C).0.8 0.84
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3/9/17, 7(28 PMHmwk: Chapter 3Page 4 of 93.2/2 points | Previous AnswersIllowskyIntroStat1 3.HW.092.Gand Hare mutually exclusive events.P(G) = 0.5P(H) = 0.2Part (a)Part (b)Part (c)Additional MaterialsSection 3.1Explain why the following statement MUST be false: Correct! To calculate , divide P(H| G) = 0.3.The events are mutually exclusive, which means they can be added together, and the sum is not0.3.
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