Ir the attack on ir will happen due to the low

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7 3 (10 pts)[CpIr(dmpe)(Et)]+is quite stable while [CpCo[P(OMe)3]2(Et)]+readily reacts with one equivalent of PMe3to produce {CpCo(H)(PMe3)[P(OMe)3]}+plus a gas that bubbles off the solution. a)(7 pts)Write out a mechanism for the reaction of [CpCo[P(OMe)b) (3 pts)Why is [CpIr(dmpe)(Et)]+considerably more stable? -
8 4. (24 points)Classify the following reactions as oxidative addition, reductive elimination, migratory insertion, elimination, -hydride elimination, ligand substitution, ligand dissociation, ligand additionoxidative coupling, hydrogenolysis(i.e., 4-center concerted H2activation & transfer), etc. There may be more than one step and that the equations are not necessarily balanced or completely list all possible products. If there is more than one step to label, make sure you list the steps in the correct order if the order is important. NO discussion or justification is necessary. , a) b) Ir(CH3)[P(OMe)3]3+ H2Ir(H)[P(OMe)3]3+ CH41) oxidative addition of H22) reductive elimination of CH4c) Cp2Zr(CH3)2+ H2Cp2ZrH(CH3) + CH4hydrogenolysis d) e) Ru(CH3)(Ph)(CO)4+ PMe3Ru(CO)4(PMe3) + Ph-CH3(toluene) 1) Reductive elimination of CH3and Ph(phenyl) to produce toluene 2) Ligand addition of PMe3f) CpRh(dmpe) + CH3I [CpRh(CH3)(dmpe)]++ I(dmpe = Me2PCH2CH2PMe2)oxidative addition of CH3I (because you are starting with an 18e- complex, only the stronger coordinating CH3coordinates) NiPR2R2PClOHNiPR2R2PClOHHmigratory insertion (hydroxide & alkene) 1) P(OMe)3ligand dissociation 2) Oxidative addition of H23) Reductive elimination of CH44) P(OMe)3

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