kinetics lab pdf.pdf

# Concentration concentration from bottle volume used

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concentration = (concentration from bottle) (volume used) (total volume) [I - ] initial = (0.20 M) (10.0 mL) = 0.040 M 50.0 mL [S 2 O 8 2 ] initial = (0.10 M) (20.0 mL) = 0.040 M 50.0 mL [S 2 O 3 2 ] initial = (0.0050 M) (5.0 mL) = 0.00050 M 50.0 mL Rate = [S 2 O 3 2 ] 2t Rate = 0.00050 M = 4.8 × 10 -6 M/s 2 (51.67 s) rate trial 2 = [I - ] x (trial 2) rate trial 1 [I - ] x (trial 1) 4.8 × 10 -6 M/s = 3.1 × 10 -6 M/s 0.040M 0.020M x 1.5 = 2.0 x log(1.5) = x log(2.0) x = 0.18 0.30 x = 0.60

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Average value for x = (trials 1 and 2) + (trials 2 and 3) + (trials 1 and 3)/3 Average value for x = (0.60) + (1.3) + (0.98) / 3 Average value for x = 0.96 5. Using the method of initial rates , show the calculation for determining the order, y, with respect to [S 2 O 8 2 ] using data from trials 3 and 4 . List the results for y using trials 4 and 5 as well as trials 3 and 5 in Results Table #4. Show how you determined the average value for y from these three results. Average value for y = (trials 4 and 5) + (trials 3 and 5) + (trials 3 and 4) / 3 Average value for x = (0.87) + (0.53) + (0.98) / 3 Average value for x = 0.79 Results Table #4 Order Trials 1 and 2 Trials 2 and 3 Trials 1 and 3 Average value for x Integer value for x x 0.60 1.3 0.98 0.96 1 Order Trials 4 and 5 Trials 3 and 5 Trials 3 and 4 Average value for y Integer value for y y 0.87 0.53 0.98 0.79 1 Overall reaction order 1 + 1 2 rate trial 3 = [S 2 O 8 2 ] y (trial 2) rate trial 4 [S 2 O 8 2 ] y (trial 1) 1.2 × 10 -5 M/s = 3.1 × 10 -6 M/s 0.040M 0.010M y 3.9 = 4.0 y log(3.9) = y log(4.0) y = 0.59 0.60 y = 0.98
6. Look back at the experimentally determined values for x and y in Results Table #4. Does the value of x vary between trials? Does the value of y vary between trials? Do you expect the values of x and y to vary between trials? Explain. The values of x and y vary between trials though I did not expect for them to because the values remain constant in the equation to determine the rate constant throughout trials. I assumed that they would vary less, but when averaged and rounded to the nearest integer the values allowed for accurate calculations of the rate constant for all trials.

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