F. The Fe(NO 3 ) 3 solution that contained NaF did not return to an orange color because it formed a new ion, FeF 6 that changed the color of the mixture. The other reactions were reversible because this did not occur. II. a. The appearance of the CuSO 4 was light blue. b. The reaction went from light blue, to light blue with white clouds mixed in, then turned to a dark blue with a tinge of purple. The NH 3 in the reaction was clear, the CuSO 4 was light blue, and the Cu(NH 3 ) 4 was dark blue, the final color.
c. The addition of HCl(aq) caused the color to change to light blue and then to clear with a blue ring on the top. The NH 3 in the solution was neutralized by the HCl(aq) in the solution which left some CuSO 4 to tint the solution. d. When NH 3 was to the solution, the color changed to a light blue on the top with a clear ring separating it from the bottom solution. The reaction set up triple equilibrium, each solution in the mixture was at equilibrium but was separated. [NH 3 ] high Solid [NH 3 ] low III. In order to shift reactions forward and reverse, one can manipulate how much heat, product, or reactant is in the system. This was seen in part I.D. of this experiment when heat was added to a reaction that was exothermic when forward. In order to compensate for the addition of heat, more reactant was made. If one wished to create more product or reactant, all one must do is add the opposite component. This was seen in part I.C. If more product is desired, then more reactant must be added; if more reactant is desired than more product must be added.
You've reached the end of your free preview.
Want to read both pages?