The average price in Sydney NSW 200 is 1522239 in Melbourne VIC 3000 is 595000

# The average price in sydney nsw 200 is 1522239 in

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and recent trends in apartment prices in the Australian capital cities after doing some research. The average price in Sydney NSW 200 is \$1522239, in Melbourne VIC 3000 is \$595000, Brisbane QLD 4000 is \$468967 , in Adelaide SA 5000 is \$485000, in Perth WA 6000 is \$415000 and in Hobart TAS 7000 is \$657595. The average number of apartment sold in Sydney is 4000, Melbourne is around 1500, Adelaide is 700, Perth is 2500 to 3000 and Hobart is just in hundreds. As we can see people living in Sydney they buy more apartments than Melbourne, Perth, Adelaide and Hobart. People in Sydney they have higher income because the price of apartment is also high and the buying number of apartment is also high over there. Question 3 a) What is the probability that an employee in Australia selected at random will be a Professional? P(Professional)= 1878.9+684.2/11573.8 = 0.2215 b) What is the probability that an employee in Australia selected at random will be a Male and a sales worker? P(male sales worker)= 232.4+161.3/11573.8 =0.0340 c) Given that a female employee is working part-time, what is the probability that she belongs to the category of Clerical and administrative workers? P( female employee belongs to clerical and administrative workers)= 502/2519.4 =0.1993 d) Visit the ABS website (Employment type, Table 6) and determine the ratio for total persons in 2013 between Owner managers of incorporated enterprises to Owner managers of unincorporated enterprises. Total owner managers of incorporated enterprise= 782.6 Total owner manager of unincorporated enterprises- 1156.2 So the ratio is 782.6/1156.2= 0. 6769 Question 4 Part A i) What is the probability that on any given week in a year there would be no rainfall? P(No rainfall)= P(x=0)= 0.0592
ii) What is the probability that there will be 3 or more days of rainfall in a week? P(x>=3) = 1-P(x=0)-P(x=1)-P(x=2) =1-0.0592-0.1674-0.2365 =0.5369 Part B i) What is the probability that in a given week there will be between 3mm and 9mm of rainfall? Mean=8.6731 SD=9.6358 P(3<=X<=9)=0.2207+0.014=0.2347 ii) What is the amount of rainfall if only 15% of the weeks have that amount of rainfall or higher? Here z=1.035 X=8.6731+(9.6358*1.035)=18.6462 Question 5 (a) a) Test for normality of the following variables using normal probability plot: Transportation expense, Distance from Residence to Work, Service time, Age, and Body mass index.

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