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Question 11 the correct answer is b to find bc when

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Question 11. The correct answer is B.To findBCwhenADis 30units,ACis 16 units,BDis 20 units, and the points are alongshown in the following, you must notice thatis the intersection ofandSo the sum of the lengths ofandwould be the same as the sumof the lengths ofand, becauseAC=AB+BC,BD=BCandAD=AB + BC+CD.By substitution,AC+BD=AB+BCCD = AB+BC+CD+BC=AD+By substituting lengthsAD+BC=AC + BD,or 30 +BC= 16 + 20, or 30+BC= 36. Subtracting 30 from both sides yieldsBC= 6.If you choseA, you probably subtracted 16 from 20. If you choseE, youprobably thought you needed more information to solve the problem.as.+CD,+BC+BC.
Question 12. The correct answer is K.There are many ways tosolve this equation. One solution is the following:Another solution method would be to graphy= 12xandy= –8(10 −x)and see where the two graphs intersect. A calculator would producethese graphs, and you could find an approximate solution. That is goodenough for this problem because the answer choices are spread apart.This is a problem in which checking your answer is easy and can pay off.Whenx= –20, the left side of the original equation is 12(–20), which is–240. The right side is –8(10 − (–20)), which simplifies to –8(10 + 20),then to –8(30), and then to –240. This solution checks. No other answerchoice would satisfy the equation.If you choseHorJ, you may have multiplied out –8(10 −x) to get –80+xor –80 −xand done the rest of the steps correctly. You could havecaught this by checking your answer. If you made an error with minussigns, you may have chosen one of the other answer choices.Question 13. The correct answer is E.Because the cardboardextends 2 inches beyond the cake on all sides, the cardboard forms arectangle whose length and width are each 4 inches longer than thelength and width of the rectangular cake, as shown in the followingfigure. The area of aluminum foil that is exposed (the shaded region inthe figure) equals the area of the foil covering the entire cardboardsurface (or area of the cardboard) minus the area of the foil covered bythe cake. So the area, in square inches, of aluminum foil exposed equals20(16) − 16(12) = 320 − 192 = 128.

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Term
Spring
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best answer, A Moveable Feast,

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