physics lab 10

# The magnitude of the magnetic field created due to

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The magnitude of the magnetic field created due to the Helmholtz coils (H), can be calculated using the coil’s radius (R) and passing current (I) using (7) Here we determine

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, (8) Where N denotes the turns of the wire in each coil. Equipment: 1. Power supply (0-500V) suitable for vacuum tubes 2. Power supply(6.3 volt, AC or DC) 3. Regulated DC power supply unit, (0-15V) 4. DC voltmeter (measure 0-500V) 5. DC ammeter (measure up to 2A) 6. Magnetic needle Procedure: After examining figure 1 (Appendix A), we set up the wiring according to Figure 3 (Appendix A) and then set the voltage of the “B-power supply” as well as the coil power supply to the minimum. Once the cathode glowed the color green we gradually raised the voltage of the “B power supply” and observed the discharge tube until a glowing electron beam appeared at around just under 200V. Last we gradually increased the voltage of the coil-power supply until the electron beam bent into a circular pattern. Data Analysis: Constant I I= d (m) Voltage r (m) r^2 0.098 262 0.049 0.002401 0.09 220 0.045 0.002025 0.082 183 0.041 0.001681 0.075 149 0.0375 0.00140625 0.062 117 0.031 0.000961 0.05 78 0.025 0.000625 Table 1: Constant I versus the radius calculations Constant V V=
d (m) Current (I) I^2 r (m) 1/r^2 0.21 1.31 1.72 0.105 90.70 0.18 1.58 2.50 0.09 123.46 0.16 1.75 3.06 0.08 156.25 0.15 1.82 3.31 0.075 177.78 0.13 2.1 4.41 0.065 236.69 Table 2: Constant voltage versus radius calculations Graph 1: Current vs. Radius with a slope of

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• Spring '12
• Dr.Phaneuf
• Physics, Magnetic Field, power supply

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