9 11 points previous answers scalcet7 33054 a

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9. 1/1 points | Previous Answers SCalcET7 3.3.054. A semicircle with diameter PQ sits on an isosceles triangle PQR to form a region shaped like a two-dimensional ice-cream cone, as shown in the figure. If A ( θ ) is the area of the semicircle and B ( θ ) is the area of the triangle, find Using the identity we can write alternative forms of the answer as . lim θ 0 + A ( θ ) B ( θ ) y = sec θ tan y = sec θ tan θ y' = sec θ (sec 2 θ ) + tan θ (sec θ tan θ ) = sec θ (sec 2 θ + tan 2 θ ). 1 + tan 2 θ = sec sec θ (1 + 2 tan 2 θ ) or sec θ (2 sec 2 θ 1). 0 0 Solution or Explanation Click to View Solution 10. 1/1 points | Previous Answers SCalcET7 3.3.005. Differentiate. y' = $$ sec ( θ )( sec 2( θ )+ tan 2( θ )) Solution or Explanation θ 2 θ ,
12/14/16, 4(12 PM hw10S3.3 Page 7 of 8 11. 1/1 points | Previous Answers SCalcET7 3.3.015. Differentiate. f ' ( x ) = $$3 excsc ( x )+3 xexcsc ( x ) 3 xexcsc ( x ) cot ( x ) Solution or Explanation Click to View Solution 12. 8/8 points | Previous Answers A stunt cyclist needs to make a calculation for an upcoming cycle jump. The cyclist is traveling 100 ft/sec toward an inclined ramp which ends 10 feet above a level landing zone. Assume the cyclist maintains a constant speed up the ramp and the ramp is inclined A o (degrees) above horizontal. With the pictured imposed coordinate system, the parametric equations of the cyclist will be: x(t) = 100t cos(A) y(t) = –16t 2 + 100t sin(A) + 10. (These are the parametric equations for the motion of the stunt cyclist.) (a) Calculate the horizontal velocity of the cyclist at time t

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