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Part 3 of 33,,ddx..
2/21/14, 2:44 PMChapter 3.5 HWPage 7 of 146.6/6 points | Previous AnswersSCalcET7 3.5.009.Find dy/dxby implicit differentiation.Solution or ExplanationClick to View Solution7.6/6 points | Previous AnswersSCalcET7 3.5.015.Find dy/dxby implicit differentiation.)y
2/21/14, 2:44 PMChapter 3.5 HWPage 8 of 148.6/6 points | Previous AnswersSCalcET7 3.5.025.Use implicit differentiation to find an equation of the tangent line to the curve at the given point.When we have so an equation of the tangent line is ysin 12x= xcos 2y, (π/2, πy= ysin 12x= xcos 2yy·cos 12x·12 + sin 12x·y'= x(−sin 2y·2y') + cos(2y/4)) ·1yy) + 0127
2/21/14, 2:44 PMChapter 3.5 HWPage 9 of 149.12/12 points | Previous AnswersConsider the equation . The graph of this curve looks like this:(a) Find the positive y-intercept: (b) Find the negative y-intercept: (c) Use implicit differentiation to find the equation of the tangent line at the intercept in (a):y= x + (d) Use implicit differentiation to find the equation of the tangent line at the intercept in (b):y= x + 10.22/22 points | Previous AnswersA bicyclist is interested in the motion of a point on the tread of her tire, so she marks the tread at one+ =2(x−1)2+ y4(x+1)2+y212