2 50 mL of the standardized HCl solutiontitrant was filled in the buret Only

2 50 ml of the standardized hcl solutiontitrant was

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2. 50 mL of the standardized HCl solution(titrant) was filled in the buret. Only for first trial : The buret was rinsed with a small amount of standardized HCl before putting the rest of the solution in 3. 10.0 mL of base B-35 was measured by 10 mL graduated cylinder and was poured in the 250 mL Erlenmeyer flask 4. 3 drops of phenolphthalein were added to the solution in the flask; the solution would turn pink 5. The Erlenmeyer flask containing unknown base B-35 was placed under the buret ready for titrating
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6. The knob of the buret was turned slowly, dripping the standardized solution into the flask. 7. The volume used was recorded into the data table when the solution passed equivalent point and turned faint pink. 8. The equipments were washed, the buret tip was cleaned with distilled water 9. Step 2 thru 9 were repeated five more times. 3. Titration of 0.500M acid with unknown base B-37: 1. The buret was cleaned three times with DI Water. 2. 50 mL of the standardized NaOH solution(titrant) was filled in the buret. Only for first trial : The buret was rinsed with a small amount of standardized NaOH before putting the rest of the solution in 3. 10.0 mL of base B-37 was measured by 10 mL graduated cylinder and was poured in the 250 mL Erlenmeyer flask 4. 3 drops of phenolphthalein were added to the solution in the flask; the solution would turn pink 5. The Erlenmeyer flask containing unknown base B-37 was placed under the buret ready for titrating 6. The knob of the buret was turned slowly, dripping the standardized solution into the flask. 7. The volume used was recorded into the data table when the solution passed equivalent point and turned faint pink. 8. The equipments were washed, the buret tip was cleaned with distilled water 9. Step 2 thru 9 were repeated five more times.
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F. Data: 1. Titration of 0.500M acid with 10mL unknown base A: Trial No. Initial Buret Reading Final Buret Reading Concentration of unknown base calculated Trial 1 0 mL 12.10 mL 0.605 M Trial 2 0 mL 12.15 mL 0.608 M Trial 3 0 mL 12.00 mL 0.600 M Trial 4 0 mL 11.95 mL 0.598 M 2. Titration of 0.500M acid with 10mL unknown base B: Trial No. Initial Buret Reading Final Buret Reading Concentration of unknown base calculated Trial 1 0 mL 9.00 mL 0.450 M Trial 2 0 mL 8.90 mL 0.445 M Trial 3 0 mL 8.95 mL 0.448 M Trial 4 0 mL 8.90 mL 0.445 M Trial 5 0 mL 8.90 mL 0.445 M
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G. Calculations and Graphs: 1. Preparing 600.0mL of 0.500M acid titrant (HCl): Volume of acid= = 600.0mL V HCl Concentration of acid = = 0.500M M HCl Concentration of stock solution = = 6.00M M stock . = . = = 50.0mL V HCl M HCl M stock V stock V HCl 6.00 M 600.0 mL . 0.500 M 2. Titration of 0.500M acid with 10.0mL unknown base A: a) Trial 1: Volume of acid = = 12.10 mL = 0.01210 L V HCl Concentration of acid = = 0.500M M HCl Volume of base used= = 10.0 mL = 0.0100 L V NaOH . = . = = 0.605 M M HCl V HCl M NaOH V NaOH M HCl 0.0100 L (0.01210 L )(0.500 M ) b) Trial 2: Volume of acid = = 12.15 mL = 0.01215 L V HCl Concentration of acid = = 0.500M M HCl Volume of base used= = 10.0 mL = 0.0100 L
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  • Fall '15
  • Neethling,Melanie
  • Chemistry, ml, Sodium hydroxide, Erlenmeyer flask

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