11 the load was applied on the cube steadily as the

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11. The load was applied on the cube steadily; as the load is applied on the cube, 12. The damaged cube was taken out, and the crushing load for the cube was noted down. The compression plate surface was cleaned for next test. 13. The remaining cubes have been using the same procedure that we use previously. Part 2 : (Tensile Strength): Required in the sand that passes assembly at 0.85mm sieve and kept at 0.6mm sieve. 1. A one hundred eighty cement were weighted and five hundred twenty –three sand were weighted. 2. Then sand was mixed with cement for one minute. 3. An one hundred of water was added to the mixture, and they were mixed by trowel for 4 minutes. 4. A 2.5 x 2.5 x 2.5 cm bone mold was painted with a thin layer of oil. 5. Then the cube was filled by the mortar paste at 2 stages. Mortar paste pleased inside the mold and then hits by the steel rod 25 hits to disturb stress equally on all parts 6. Then the samples were taken out from the template and kept in open air for 24 hour, and then they were sinking in a water basin for a week.
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7. After that the samples were taken out from the basin, and the samples were dried with paper, and weighed 8 8. The sample was put in the tensile machine, and the load was applied. The application of load was discontinued when the sample was cut, and the load was read at the instant when it was cut. 9. The same procedure was used for the remaining sample. 4. Data & Calculations: Part A: (Compressive Strength): We have obtained this data by compression testing machine: Cube number Length (mm) Width (mm) Surface area (mm²) Compressive force(KN) Compressive stress (MPa) 1 70.0 71.0 70*71=4970 148.7 29.92 2 70.5 71.0 70.5*71=5005. 5 137.1 27.39 3 71.0 72.0 71*72=5112 142.3 27.84 For Compressive stress column we obtained the values by dividing the compressive force on the Surface area. Cube #1: Compressive stress= (148.7*10^3)/(4970 *10^-6)=29.92 MPa. Cube #2: Compressive stress= (137.1*10^3)/(5005.5 *10^-6)=27.39 MPa. Cube #3: Compressive stress= (142.3*10^3)/(5112 *10^-6)=27.84 MPa.
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Average Compressive force for the cubes = 148.7+137.1+142.3 / 3 = 142.7 KN. Average Compressive stress for the cubes = 29.92+27.39+27.84 / 3= 28.38 MPa. 9 Part B: (Tensile Strength): Sample number Area (mm²) Tension force(KN) Stress (MPa) 1 30.5*25.5=777.7 5 0.4 Tension force/area 0.4/777.75=0.514 2 30.5*25.5=777.7 5 0.38 Tension force/area 0.38/777.75=0.489 3 27.5*25.5=701.2 5 0.24 Tension force/area 0.24/701.25=0.342 Average Tension force for the samples = 0.4+0.38+0.24/3=0.34KN.
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