Hw 11 Solutions

# Is the distance along the direction of flow between

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is the distance along the direction of flow between the points where the temperature is T H and T C . Thus,

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The thermal conductivity is found in Table 18-6 of the text. Recall that a change in Kelvin temperature is numerically equivalent to a change on the Celsius scale. 54. We use Eqs. 18-38 through 18-40. Note that the surface area of the sphere is given by A = 4 π r 2 , where r = 0.500 m is the radius. (a) The temperature of the sphere is T = (273.15 + 27.00) K = 300.15 K. Thus (b) Now, T env = 273.15 + 77.00 = 350.15 K so (c) From Eq. 18-40, we have 55. We use P cond = kA Δ T / L A / L . Comparing cases ( a ) and ( b ) in Figure 18–42, we have Consequently, it would take 2.0 min/4 = 0.50 min for the same amount of heat to be conducted through the rods welded as shown in Fig. 18-42( b ). 71. Let m w = 14 kg, m c = 3.6 kg, m m = 1.8 kg, T i 1 = 180°C, T i 2 = 16.0°C, and T f = 18.0°C. The specific heat c m of the metal then satisfies
which we solve for c m : 90. We use Q = – λ F m ice = W + Δ E int . In this case Δ E int = 0. Since Δ T = 0 for the ideal gas, then the work done on the gas is
• Fall '11
• Robbert

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