181_Lab_7a

# Theory procedure 1 connect the six circuit leads to

This preview shows pages 1–5. Sign up to view the full content.

Theory : Procedure : 1) Connect the six circuit leads to their proper components excluding for one battery lead. 2) After TA approves circuit, set R to 300 ohms and close the switch S. Write down the readings for the current, voltage, and power output (I*V) for the given resistance values (300 – 33). 3) Use caution as R approaches its maximum power output, r, and record results accurately. Data/Analysis: Table 1 Resistance (ohms) I (milliamps) V (Volts) Power (Amps*Volts) [W] 300 8.2 2.40 0.0197 200 11.2 2.25 0.0252 100 18.8 1.90 0.0357 90 20.2 1.80 0.0364 80 22.0 1.75 0.0385 70 23.8 1.70 0.0405 60 26.0 1.60 0.0416

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
50 28.8 1.50 0.0432 48 29.4 1.46 0.0429 46 30.1 1.41 0.0424 44 30.7 1.38 0.0424 42 31.5 1.35 0.0425 41 31.8 1.32 0.0420 40 32.1 1.30 0.0417 39 32.5 1.29 0.0419 38 33.0 1.28 0.0422 37 33.3 1.27 0.0423 36 33.7 1.25 0.0421 35 34.2 1.24 0.0424 34 34.8 1.21 0.0421 33 35.1 1.19 0.0418 The Power is computed by simply multiplying the voltage and amperage values. For example:
Problems: 1) Show that Eq. (4) follows from Eq. (1) and (3), and that Eq. (4) with Eq. (5) gives P max =E 2 /4r. Eq. (1) and (3) show us that: And that: Therefore: And finally, our result matches Eq. (4): Now, we will prove that Eq. (4) and (5) can be combined to achieve the desired equation: Eq (5) states that R=r when P is at a maximum Therefore:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Which can be reduced for the desired result: 2) Determine the experimental values for E and r using the data from the first graph and equation (2).
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern