Advantages of Client/Server Networks:1.Centralized control: Client/server networks have a central server thatcontrols access, resources, and security. This centralized managementsimplifies administration and allows for better control and enforcement ofpolicies.2.Scalability: Client/server networks can handle large-scale deploymentsefficiently. Servers can be upgraded or added to handle increased demand,ensuring scalability as the network grows.3.Enhanced security: Centralized control enables easier implementation ofsecurity measures, such as firewalls, access controls, and encryption.Critical data and resources can be protected more effectively.4.Reliability: Client/server networks can offer higher reliability as dedicatedservers are designed for continuous operation. Redundancy and backupmechanisms can be implemented to minimize downtime.Disadvantages of Client/Server Networks:1.Cost: Client/server networks generally require dedicated servers, whichcan be costly to acquire, maintain, and upgrade. The initial investment andongoing operational expenses may be higher compared to P2P networks.2.Dependency on the server: If the central server fails or experiencesdowntime, the network's functionality and access to resources can besignificantly impacted.3.Complexity: The centralized nature of client/server networks introducesadditional complexity in terms of setup, configuration, and administration.Skilled IT personnel are often required to manage and maintain the serverinfrastructure.4.Potential performance bottlenecks: In client/server networks, all requestsand data transmissions must pass through the server, which can create apotential performance bottleneck, especially if the server becomesoverloaded with requests.4-Determine the maximum channel capacity in bps of a voice grade channel having asignal power of 34 db and noise power of 4 db.To determine the maximum channel capacity of a voice grade channel, we canuse the Shannon Capacity formula:C = B * log2(1 + (S/N))
Where: C is the channel capacity in bits per second (bps), B is the bandwidth inhertz (Hz), S is the signal power in watts, N is the noise power in watts.In this case, we have the signal power (S) as 34 dB and the noise power (N) as 4dB. We need to convert these values to watts before applying the formula.Converting signal power from dB to watts: S_watts = 10^(S/10) S_watts =10^(34/10) S_watts = 10^3.4 S_watts = 2511.886432Converting noise power from dB to watts: N_watts = 10^(N/10) N_watts =10^(4/10) N_watts = 10^0.4 N_watts = 2.511886432Now, let's assume a voice grade channel typically has a bandwidth of 4000 Hz (4kHz). We can substitute the values into the formula:C = 4000 * log2(1 + (2511.886432 / 2.511886432))Simplifying the equation:C = 4000 * log2(1 + 1000)C = 4000 * log2(1001)C = 4000 * 9.965784C ≈ 39863.136 bpsTherefore, the maximum channel capacity of the voice grade channel isapproximately 39,863.136 bps.
Want to read all 38 pages?
Previewing 16 of 38 pages Upload your study docs or become a member.
Want to read all 38 pages?
Previewing 16 of 38 pages Upload your study docs or become a member.
End of preview
Want to read all 38 pages? Upload your study docs or become a member.