If we assume that s n converges say s n s s negationslash 0 then for large n s

If we assume that s n converges say s n s s

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9. If we assume that (sn) converges, saysns, snegationslash= 0, then for largen, snsandsn+1s. Substituting into the recursion formula, we gets=s2+x2s2s2=s2+xs=x. 5
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  • Tn, Natural number, Sn

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