O api n 2 content in gas co 2 content in gas h 2 s

This preview shows page 1 - 6 out of 6 pages.

o API N 2 content in gas: CO 2 content in gas: H 2 S content in gas: o F o F
Image of page 1

Subscribe to view the full document.

Solution gas-oil ratio at bottom hol 339.39 scf/stb 60.44 Oil formation volume factor at bot 1.18 rb/stb 1.18 Volume associated with 1 stb of oil 16.56 cf 0.47 Fluid density at bottom hole = 29.94 lb/cf 478.58 The average fluid density = 20.46 lb/cf 327.09 44.63 lb/day-ft 66.31 Friction factor = 0.0084 0.01 Friction term = 390.50 99785 Error in liquid rate = 0.00 stb/d 0.00 Bottom hole pressure = 1873 psia 12.74 Liquid production rate = 1,127 stb/d 179 Inertial force (D r v) = (lb/cf) 2 M = 350.17 ( γ o + WOR γ w )+ GOR ρ air γ g R s = γ g [ p 18 10 0.0125 API 10 0.00091 t ] 1.2048 B o = 0.971 + 0.000147 [ R s ( γ g γ o ) 0 .5 + 1.25 t ] 1 .175 V m = 5.615 ( B o + WOR B w )+( GOR R s ) ( 14.7 p )( T 520 ) ( z 1.0 ) ( Dρv ) = 1.4737 × 10 5 Mq o D f m = 4 × 10 1.444 2.5 log ( Dρv ) p wf = p wh + ( ¯ ρ + ¯ k ¯ ρ ) H 144
Image of page 2
0 MPa 3000 psia m 1.66 in MPa 500 psia 1 stb/d-psi 1000 scf/bbl 1333.33 scf/stb % 281.715940926745 bbl/d water 0.33333 bbl/stb 1 for fresh water 30 1 for fresh water 1.05 1 for fresh water 1 for air 0.65 1 for air mole fraction 0 mole fraction mole fraction 0 mole fraction mole fraction 0 mole fraction 1.2 rb/stb 100 m 5000 ft 150 1 for fresh water kg m hole node. ion" button; and 4) sm 3 /d-MPa sm 3 /m 3 o API rm 3 /sm 3 o C o F o C o F sm 3 /m 3 rm 3 /m 3 m 3 kg/m 3
Image of page 3

Subscribe to view the full document.

kg/day-m MPa 1,127 bbl/d liquid 845.148 stb/d oil 1,127 sm 3 /m 3 rm 3 /m 3 m 3 kg/m 3 kg/m 3 (kg/cm) 2 sm 3 /d sm 3 /d wh + ( ¯ ρ + ¯ k ¯ ρ ) H 144 q = J ¿ ( ¯ p p wf )
Image of page 4
0.13833333 ft Gas rate = 1126864 scf/d Z-factor Calculations: Ppc = 670.5 psia Tpc = 373.355 Wellhead Bottom hole o R
Image of page 5

Subscribe to view the full document.

Ppr = 0.745712 2.79364092 Tpr = 1.499913 1.63383375 A = 0.417544 0.48521254 B = 0.241867 1.05943151 C = 0.075659 0.06377348 D = 0.968267 0.99293848 z = 0.931813 0.84053747
Image of page 6
  • Fall '19

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern

Ask Expert Tutors You can ask 0 bonus questions You can ask 0 questions (0 expire soon) You can ask 0 questions (will expire )
Answers in as fast as 15 minutes