c) [1 mark]
D.
d) [2 marks]
15, 189, 138
(Need all three parts for the 2 marks; no part marks here)
e)[1 mark]
E.
Monthly sales are more variable in Vancouver compare to Toronto
Question 4 (10 marks)
a) (i) [1 mark]
A.
Negative, moderately strong
(ii) [1 mark]
B.
Become stronger negative
b) [3 marks]
Large neg.; Large Pos.; Small
c) [5 marks]
False, False, False, False, True
Q
uestion 5 (12 marks)
a) [2 marks]
= 74.73 – 3.19
x
(Reason:
= 59.5 –(3.19)(5.4) = 74.73)
b) [2 marks]
0.95
(Reason: Rearrange the formula for
= (3.19)(3.3/11.1) = 0.95)
c) [1 mark] “
decreases by 3.19
”
d) [1 mark]
90%
(Reason:
r
2
= (0.95)
2
= 0.90 or 90%
e) [1 mark]
49
(Reason: (8) = 74.73 – 3.19(8) = 49.21)
f) [2 marks] Residual = 11 (Reason: y–
= 60 – 49 =11)
Yes, this is an outlier since the resident is more than 2.5 ’s away from 0.
g) [1 mark]
57.5
(Reason: Since
x
is unknown, just use the mean of
y
.)
h) [2 marks]
35 to 80
(Reason: Use the 689599.7 Rule, i.e. 57.5±2(11.1) = 35.3, 74.7)
1
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View Full DocumentQuestion 6 (18 marks)
a) [2 marks]
A.
I and II only
b) (i) [2 marks] Mean =
20
; SD =
10
Computations: Pr(Z > z) = 0.5 => z = 0, so X = μ + zσ => 20 = μ + 0 => μ = 20
Pr(Z > z) = 0.1587 => z = 1, so X = μ + zσ => 30 = 20 + 1σ => σ = 10
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 Winter '10
 E.Fowler
 Sauder School of Business

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