calculating the mass and mass percent of K2C2O4for each run, I ended up with an average mass percent of 15.7%. The average absolute deviation was calculated to be 0.1%. Therefore 15.7% 0.1% of unknown A is K2C2O4. For some of the runs, more titrant may have been added than needed. This was indicated by the darker purple color that appeared rather than the lighter purple color I was aiming for while titrating. This may have affected my results and calculations. It was crucial in this experiment to rinse and fill the buret with the titrant to remove any water or other chemical residues left behind. If water droplets remained in the buret, the water could have affected the data. It was also important not to shoot over the end point of the titration because this would result in a larger volume of titrant used. A larger volume of titrant means a higher calculated concentration of titrant too. This change would affect the rest of the calculations and data. I could have improved this experiment by improving my titration techniques and trying to stay as close to the end point as possible. During this experiment, I learned how to use titrations and half equations to calculate the mass percent of a substance in a given unknown.
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