The molar mass of this compound is 39932 gmol 50 Define physical and chemical

The molar mass of this compound is 39932 gmol 50

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The molar mass of this compound is: 399.32 g/mol 50. Define physical and chemical properties. (4.01) Physical properties can be observed (look, feel, etc) without altering the chemical identity of the substance. Chemical properties 51. List three physical and three chemical properties. (4.01) A few examples of physical properties are color, density, ductility and phase changes. A few examples of chemical properties are flammability, chemical reactivity and oxidation state. 52.Define extensive and intensive properties. Give an example of each. (4.01)
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53. When the following reaction is balanced with the lowest possible whole number coefficients, what is the coefficient in front of CO 2 ? (4.02) C 2 H 4 + O 2 CO 2 + H 2 O Let’s make a table to help us balance the equation. Element # Reactants # Products C 2 1 H 4 2 O 2 3 Since O is found in two different chemicals on the right side, I will balance that last (my personal strategy). Let’s start with C. C 2 H 4 + O 2 2 CO 2 + H 2 O Element # Reactants # Products C 2 1 2 H 4 2 O 2 3 Now, let’s balance H’s: C 2 H 4 + O 2 2 CO 2 + 2 H 2 O Element # Reactants # Products C 2 1 2 H 4 2 4 O 2 3 Now, let’s recount our O’s as we changed the total number of O’s on the right side by placing the 2 in front of both the products: C 2 H 4 + O 2 2 CO 2 + 2 H 2 O Element # Reactants # Products C 2 1 2 H 4 2 4 O 2 3 6 Finally, let’s balance O:
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C 2 H 4 + 3 O 2 2 CO 2 + 2 H 2 O Element # Reactants # Products C 2 1 2 H 4 2 4 O 2 3 3 6 To answer the question, the coefficient in front of CO 2 when balanced, is a 2 . 54. Pick two chemicals, that when placed together would NOT produce a successful single-replacement reaction. (4.03) A single replacement reaction is where a single element, a metal, reacts with an ionic compound. We need the activity series, which is found in the lesson. In order to write a reaction that would NOT react, the easiest way is to pick an element from the bottom to put by itself. For example: Au. Then, we can write any ionic compound that has a metal which is found higher than Au. An example: LiNO 3 . So, if we write: Au + LiNO 3 ? The answer is no reaction as gold, Au, is lower on the activity series. Thus, it is not reactive enough to replace lithium. Au + LiNO 3 no reaction
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